x^2+48x-3600=0

Solution for x^2+48x-3600=0 equation:

x^2+48x-3600=0

a = 1; b = 48; c = -3600;
Δ = b2-4ac
Δ = 482-4·1·(-3600)
Δ = 16704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16704}=\sqrt{576*29}=\sqrt{576}*\sqrt{29}=24\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-24\sqrt{29}}{2*1}=\frac{-48-24\sqrt{29}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+24\sqrt{29}}{2*1}=\frac{-48+24\sqrt{29}}{2}
$